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4.9x^2+2.6185x-10=0
a = 4.9; b = 2.6185; c = -10;
Δ = b2-4ac
Δ = 2.61852-4·4.9·(-10)
Δ = 202.85654225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.6185)-\sqrt{202.85654225}}{2*4.9}=\frac{-2.6185-\sqrt{202.85654225}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.6185)+\sqrt{202.85654225}}{2*4.9}=\frac{-2.6185+\sqrt{202.85654225}}{9.8} $
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